document.write( "Question 998746: In quadrilateral MATH, angle M = x(degrees), angle A = 3x(degrees), angle T = (x-30)(degrees). What is the measure of an exterior angle at H, expressed in terms of x? \n" ); document.write( "
Algebra.Com's Answer #616490 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Let y = measure of the exterior angle at H\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "For any given interior angle, the exterior angle is simply 180 minus that given angle. For example, if the interior angle is 30 degrees, then the exterior angle is 180 - 30 = 150 degrees. If the interior angle is x degrees, then the exterior angle is 180 - x degrees.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "angle M = x(degrees) \n" ); document.write( "exterior to angle M = 180 - x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "angle A = 3x(degrees) \n" ); document.write( "exterior to angle A = 180 - 3x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "angle T = (x-30)(degrees) \n" ); document.write( "exterior to angle T = 180 - (x-30) \n" ); document.write( "exterior to angle T = 180 - x+30 \n" ); document.write( "exterior to angle T = 210 - x\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Summary so far: \n" ); document.write( "exterior to angle M = 180 - x \n" ); document.write( "exterior to angle A = 180 - 3x \n" ); document.write( "exterior to angle T = 210 - x \n" ); document.write( "exterior to angle H = y\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In any polygon, the sum of the exterior angles is 360 degrees. This applies to quadrilaterals because they are 4 sided polygons. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(exterior angle for M)+(exterior angle for A)+(exterior angle for T)+(exterior angle for H) = 360 \n" ); document.write( "(180-x)+(180-3x)+(210-x)+(y) = 360 \n" ); document.write( "180-x+180-3x+210-x+y = 360 \n" ); document.write( "570-5x+y = 360 \n" ); document.write( "570-5x+y+5x = 360+5x \n" ); document.write( "570+y = 360+5x \n" ); document.write( "570+y-570 = 360+5x-570 \n" ); document.write( "y = -210+5x \n" ); document.write( "y = 5x-210\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "At the top we said \"Let y = measure of the exterior angle at H\" \n" ); document.write( "So because y = 5x-210, the exterior angle measure of H in terms of x is 5x-210 \n" ); document.write( " \n" ); document.write( " |