document.write( "Question 998703: Solve e^2x-10e^x+24=0, it has two solutions.\r
\n" ); document.write( "\n" ); document.write( "I am not sure how to solve it,but I tried to solve it and I will provide my step.\r
\n" ); document.write( "\n" ); document.write( "Step 1 - use quadratic formula
\n" ); document.write( "e^2x-10e^x+24=0
\n" ); document.write( "-b +/- sqrt(b^2-4ac)/2a\r
\n" ); document.write( "\n" ); document.write( "-[-10] +/- sqrt(-10^2-4(1)(24)/2(1)
\n" ); document.write( "10 +/- sqrt(4)/2
\n" ); document.write( "10 +/- 2/2
\n" ); document.write( "10 +/- 1
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Algebra.Com's Answer #616454 by ikleyn(52793)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "Solve e^2x-10e^x+24=0
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\n" ); document.write( "\n" ); document.write( "Factor\r
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\n" ); document.write( "\n" ); document.write( "\"e%5E2x-10e%5Ex%2B24\" = \"%28e%5Ex-4%29%2A%28e%5Ex-6%29\".\r
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\n" ); document.write( "\n" ); document.write( "Now the roots are \r
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\n" ); document.write( "\n" ); document.write( "\"e%5Ex\" = \"4\"   ----->  x = \"ln%284%29\",     and\r
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\n" ); document.write( "\n" ); document.write( "\"e%5Ex\" = \"6\"   ----->  x = \"ln%286%29\".\r
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