document.write( "Question 998703: Solve e^2x-10e^x+24=0, it has two solutions.\r
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document.write( "I am not sure how to solve it,but I tried to solve it and I will provide my step.\r
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document.write( "Step 1 - use quadratic formula
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document.write( "e^2x-10e^x+24=0
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document.write( "-b +/- sqrt(b^2-4ac)/2a\r
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document.write( "-[-10] +/- sqrt(-10^2-4(1)(24)/2(1)
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document.write( "10 +/- sqrt(4)/2
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document.write( "10 +/- 2/2
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document.write( "10 +/- 1
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Algebra.Com's Answer #616454 by ikleyn(52793)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "Solve e^2x-10e^x+24=0 \n" ); document.write( "-----------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Factor\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now the roots are \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |