document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=998648>Question 998648</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An airplane is headed 123 degrees with an air speed of 310 mph with a wind of 40 mph on a bearing of 200 degrees. Find the ground speed to the nearest mph, and the true course of the airplane to the nearest degree? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #616430 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=616430\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  An airplane is headed 123 degrees with an air speed of 310 mph with a wind of 40 mph on a bearing of 200 degrees. Find the ground speed to the nearest mph, and the true course of the airplane to the nearest degree? <BR>\n" );
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document.write( "Assume the starting point is (0,0)<BR>\n" );
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document.write( "Let end point coordinates be (x,y)<BR>\n" );
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document.write( "x = 310*cos(123)+40*cos(200) = -206.43<BR>\n" );
document.write( "y = 310*sin(123)+40*sin(200) = 246.31<BR>\n" );
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document.write( "distance = sqrt[206.43^2+246.31^2] = 321.37 miles<BR>\n" );
document.write( "bearing = arctan(246.31/-206.43) = -50 degrees = 310 degrees<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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