document.write( "Question 998642: Please show step by step. Thanks\r
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\n" ); document.write( "\n" ); document.write( "An unknown radioactive element decays into non-radioactive substances. In 980 days the radioactivity of a sample decreases by 52 percent. \r
\n" ); document.write( "\n" ); document.write( " (a) What is the half-life of the element?
\n" ); document.write( " half-life: (days) \r
\n" ); document.write( "\n" ); document.write( " (b) How long will it take for a sample of 100 mg to decay to 77 mg?
\n" ); document.write( " time needed
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Algebra.Com's Answer #616413 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
General model \"y=pe%5E%28-kt%29\" and you have starter information so that you can find the value for k. Also half-life.\r
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\n" ); document.write( "\n" ); document.write( "The 52% decrease after 980 days,
\n" ); document.write( "\"y%2Fp=e%5E%28-kt%29\"
\n" ); document.write( "\"ln%28y%2Fp%29=-kt\"
\n" ); document.write( "\"ln%28p%2Fy%29=kt\"-----------------------(and this step you will use again).
\n" ); document.write( "\"highlight%28k=%281%2Ft%29ln%28p%2Fy%29%29\"
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\n" ); document.write( "Information given in description is \"system%28t=980%2Adays%2Cp=100%2Cy=48%29\", and this \"48\" is because that is what remains as percent after 52% decayed.\r
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\n" ); document.write( "\n" ); document.write( "You should be able to do the rest of the questions and steps.\r
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\n" ); document.write( "Still wanted more steps to the solutions---\r
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\n" ); document.write( "\n" ); document.write( "(a) Half-Life\r
\n" ); document.write( "\n" ); document.write( "Return to this part: \"ln%28p%2Fy%29=kt\"
\n" ); document.write( "What was k? Substitute the given values in the main part of the description!
\n" ); document.write( "\"k=ln%28100%2F48%29%2F980\"
\n" ); document.write( "\"highlight%28k=7.489%2A10%5E%28-4%29%29\"
\n" ); document.write( "The model for decay is now \"highlight_green%28y=pe%5E%28-0.0007489%2At%29%29\".
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\n" ); document.write( "The step to find any time t,
\n" ); document.write( "\"t=ln%28p%2Fy%29%2Fk\"
\n" ); document.write( "You know the needed values for finding half-life with this formula, so substitute THEM.
\n" ); document.write( "\"t=ln%281%2F%281%2F2%29%29%2F0.0007489\"
\n" ); document.write( "\"highlight%28t=925%2Adays%29\"----the half-life.\r
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\n" ); document.write( "\n" ); document.write( "(b) How long to decay from 100 mg to 77 mg ?
\n" ); document.write( "You have the formula and model to use.
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