document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=998599>Question 998599</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Im not sure if I chose the correct topic but could you please help me solve this equation? the original function is: f(x)=(2x)/(x-3). I have to find the inverse relation so switch x and y. i have come up with the equation: x=(2y)/(y-3). i need help solving for y. so far i have xy-3x=2y </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #616368 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=616368\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> f(x)=(2x)/(x-3)\r<BR>\n" );
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document.write( "y=(2x)/(x-3) ... replace f(x) with y\r<BR>\n" );
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document.write( "x=(2y)/(y-3) ... swap x and y; now solve for y\r<BR>\n" );
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document.write( "x(y-3)=2y ... Multiply both sides by y-3.\r<BR>\n" );
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document.write( "xy-3x=2y ... Distribute\r<BR>\n" );
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document.write( "xy=2y+3x ... Add 3x to both sides.\r<BR>\n" );
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document.write( "xy-2y=3x ... Subtract 2y from both sides.\r<BR>\n" );
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document.write( "y(x-2)=3x ... Factor\r<BR>\n" );
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document.write( "y=3x/(x-2) ... Divide both sides by x-2.\r<BR>\n" );
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document.write( "The inverse function is <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE f^{-1}(x) = \frac{3x}{x-2}\"> </SPAN>\n" );
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