document.write( "Question 998586: A man could arrive on time for an appointment if he drove his car at 40 mph; however, since he left the house 15 minutes late, he drove the car at 50 mph and arrived 3 minutes early for the appointment. How far from his house was his appointment? \n" ); document.write( "
Algebra.Com's Answer #616363 by ankor@dixie-net.com(22740)\"\" \"About 
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A man could arrive on time for an appointment if he drove his car at 40 mph; however,
\n" ); document.write( " since he left the house 15 minutes late, he drove the car at 50 mph and arrived 3 minutes early for the appointment.
\n" ); document.write( " How far from his house was his appointment?
\n" ); document.write( ":
\n" ); document.write( "Since we are dealing in mph, change the minutes to hr
\n" ); document.write( "15 min: 15/60 = .25 hrs
\n" ); document.write( " 3 min: 3/60 = .05 hrs
\n" ); document.write( ":
\n" ); document.write( "Let t = his normal drive time to work in hrs
\n" ); document.write( "then
\n" ); document.write( "40t = the distance to work
\n" ); document.write( "Write a distance equation; dist = speed * time
\n" ); document.write( "50(t-.25 + .05) = 40t
\n" ); document.write( "50(t - .20) = 40t
\n" ); document.write( "50t - 10 = 40t
\n" ); document.write( "50t - 40t = 10
\n" ); document.write( "10t = 10
\n" ); document.write( "t = 1 hr normal time to work
\n" ); document.write( "therefore
\n" ); document.write( "40(1) = 40 mi to work
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Confirm this by finding the dist when he went 50 mph for 48 min (.8hrs)
\n" ); document.write( "50(1-.25+.05) = 50(.8) = 40 mi also \n" ); document.write( "
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