document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=998543>Question 998543</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 3 more than twice the width. The area is 44 square inches. Find the dimension  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #616357 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=616357\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A = LW = 44<BR>\n" );
document.write( "and<BR>\n" );
document.write( "L = 3 + 2W<BR>\n" );
document.write( "now substitute this into the first equation...<BR>\n" );
document.write( "(3+2W)W=44<BR>\n" );
document.write( "3W+2W^2=44<BR>\n" );
document.write( "Rearranging<BR>\n" );
document.write( "2W^2 + 3W - 44 =  0<BR>\n" );
document.write( "Factoring we get<BR>\n" );
document.write( "(2W + 11)(W - 4) = 0<BR>\n" );
document.write( "so that<BR>\n" );
document.write( "W = 4 inches<BR>\n" );
document.write( "L = 11 inches </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );