document.write( "Question 998572: Find in the form y=ax^2+bx+c, the equation of the quadratic whose graph cuts the x-axis at 5, passes thrpugh (2,5) and has axis of symmetry x=1 \n" ); document.write( "
Algebra.Com's Answer #616338 by stanbon(75887)\"\" \"About 
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Find in the form y=ax^2+bx+c, the equation of the quadratic whose graph cuts the x-axis at 5, passes through (2,5) and has axis of symmetry x=1
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\n" ); document.write( "x-intercept at (5,0) which is 4 to the right of the axis of symmetry.
\n" ); document.write( "x-intercept at (-3,0) which is 4 to the left of the axis of symmetry.
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\n" ); document.write( "Form:: y = a(x-5)(x+3)+c
\n" ); document.write( "Using (2,5), solve for \"c\"::
\n" ); document.write( "5 = a(-3)(5)+c
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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