document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=998544>Question 998544</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The height of a triangle is 2 more than twice the base. The area is 20 square feet. Find the base  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #616335 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=616335\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The area of a triangle is <BR>\n" );
document.write( "A= (1/2)bh<BR>\n" );
document.write( "Since h = b+2 we can substitute and solve<BR>\n" );
document.write( "20 = (1/2)b(b+2)<BR>\n" );
document.write( "40 = b^2 + 2b<BR>\n" );
document.write( "b^2 + 2b - 40 = 0<BR>\n" );
document.write( "Use the quadratic formula here because it is not factorable...<BR>\n" );
document.write( "b = (-2 +- sqrt(4 + 160)) / 2<BR>\n" );
document.write( "and get<BR>\n" );
document.write( "b = (-2 +- 12.65) / 2  (must be positive here so...)<BR>\n" );
document.write( "b = (-2 + 12.65) / 2 = 5.33 or so... </SPAN>\n" );
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