document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=998549>Question 998549</A>: <I><SPAN STYLE=\"word-break: break-all;\"> For the sequence given by an=4n+5, answer the following:\r<BR>\n" );
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document.write( "a. Find the first five terms\r<BR>\n" );
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document.write( "b. Find the sum of the first 25 terms </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #616324 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=616324\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Given the rule an=4n+5, the first five terms are for n=1 to n=5...<BR>\n" );
document.write( "9,13,17,21,25<BR>\n" );
document.write( "The sum of the first twenty-five terms is found by (a25 = 105)...<BR>\n" );
document.write( "Sn = (n/2)(a1 + an) = (25/2)(9 + 105) = 1425 </SPAN>\n" );
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