document.write( "Question 85428: During rush hour, Fernando can drive 20 miles using the side roads in the same time that it takes to travel 15 miles on the freeway. If Fernando's rate on the side roads is 9 mi/h faster than his rate on the freeway, find his rate on the side roads. \n" ); document.write( "
Algebra.Com's Answer #61630 by scianci(186)\"\" \"About 
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distance = (rate)(time)\r
\n" ); document.write( "\n" ); document.write( "rate = \"distance%2Ftime\"\r
\n" ); document.write( "\n" ); document.write( "\"20%2Ft\" = \"15%2Ft\" + 9\r
\n" ); document.write( "\n" ); document.write( "Multiply by t:\r
\n" ); document.write( "\n" ); document.write( "t(\"20%2Ft\" = \"15%2Ft\" + 9)
\n" ); document.write( "Cancel denominators:
\n" ); document.write( "20 = 15 + 9t
\n" ); document.write( "Subtract 15 from both sides:
\n" ); document.write( "5 = 9t
\n" ); document.write( "Divide both sides by 9:
\n" ); document.write( "5/9 = t\r
\n" ); document.write( "\n" ); document.write( "\"20%2F%285%2F9%29\" = 20\"%7B9%2F5\") = 36 MPH
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