document.write( "Question 998503: If you make a cardboard box that is twice as wide, twice as tall, and twice as long as a cardboard box that you already have, how will the volume of the larger box compare with the volume of the original box? (Will the larger box be twice as big, 3 times as big, 4 times as big, etc.?) \n" ); document.write( "
Algebra.Com's Answer #616262 by Theo(13342)\"\" \"About 
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the volume will be 8 times as large.\r
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\n" ); document.write( "\n" ); document.write( "let the dimensions of your original box be x,y,z\r
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\n" ); document.write( "\n" ); document.write( "x is the width,
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\n" ); document.write( "z is the length.\r
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\n" ); document.write( "\n" ); document.write( "the volume is therefore x * y * z\r
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\n" ); document.write( "\n" ); document.write( "now you double each dimension, so the dimensions are now 2 * x, 2 * y, 2 * z.\r
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\n" ); document.write( "\n" ); document.write( "the volume is therefore 2 * x * 2 * y * 2 * z = 8 * (x * y * z)\r
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\n" ); document.write( "\n" ); document.write( "since the volume of the original box is equal to x * y * z, then:\r
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\n" ); document.write( "\n" ); document.write( "the volume of the larger box is equal to 8 * the volume of the original box.\r
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