document.write( "Question 998500: My age is 4 times the difference of my age after 4 years and my age 3 years back. How old am I ? \n" ); document.write( "
Algebra.Com's Answer #616253 by ikleyn(52803)\"\" \"About 
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\n" ); document.write( "Let  x  be your present age.\r
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\n" ); document.write( "\n" ); document.write( "Then your age after  4  years is  x+4,  and your age  3  years before is  x-3.\r
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\n" ); document.write( "\n" ); document.write( "The condition says that\r
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\n" ); document.write( "\n" ); document.write( "x = 4*((x+4) - (x-3)) = 4*(x + 4 -x + 3) = 4*7 = 28.\r
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\n" ); document.write( "\n" ); document.write( "Answer.  28 years.\r
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