document.write( "Question 998450: Really need help on logarithm problems!\r
\n" ); document.write( "\n" ); document.write( "log(x)+log(x-15)=2\r
\n" ); document.write( "\n" ); document.write( "ln(x+12)-ln(x)= ln(x+5)\r
\n" ); document.write( "\n" ); document.write( "e^2x+2e^x-3=0
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Algebra.Com's Answer #616208 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
log(x)+log(x-15)=2\r
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\n" ); document.write( "\n" ); document.write( "Assumed base ten:
\n" ); document.write( "\"log%28%28x%29%29%2Blog%28%28x-15%29%29=2\"\r
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\n" ); document.write( "\n" ); document.write( "Rule of Logarithms says do this.
\n" ); document.write( "\"log%28%28x%28x-15%29%29%29=2\"\r
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\n" ); document.write( "\n" ); document.write( "Put into exponential form:
\n" ); document.write( "\"10%5E2=x%28x-15%29\"\r
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\n" ); document.write( "\n" ); document.write( "Simpler algebra from there.
\n" ); document.write( "\"x%5E2-15x-100=0\"
\n" ); document.write( "\"%28x-10%29%28x%2B5%29=0\"
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\n" ); document.write( "Either x=10 or x=-5.\r
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\n" ); document.write( "\n" ); document.write( "Review laws of exponents and rules of logarithms.
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