document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=998337>Question 998337</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given 5x+2y-6=0 write equation of a line that is perpendicular going through point (0,-3).<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #616128 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=616128\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the slope of this line first.<BR>\n" );
document.write( "5x + 2y - 6 = 0<BR>\n" );
document.write( "2y = -5x + 6<BR>\n" );
document.write( "y = (-5/2)x + 3<BR>\n" );
document.write( "This time you need a slope of 2/5 (it's the negative reciprocal)...<BR>\n" );
document.write( "So using the point and y = mx + b, we get<BR>\n" );
document.write( "-3 = (2/5)(0) + b<BR>\n" );
document.write( "and b = -3<BR>\n" );
document.write( "so your line is<BR>\n" );
document.write( "y = (2/5)x - 3 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );