document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=998312>Question 998312</A>: <I><SPAN STYLE=\"word-break: break-all;\"> By using the formula for the sum of n terms of a Geometric Progression, find the sum of the first 10 terms of the series 62.5, -25, 10, -4......, correct to 3 decimal place. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #616118 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=616118\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> By looking at this sequence, you can see that the ratio involved is (-2/5)...thus the remaining terms multiply by -0.4...and we get<BR>\n" );
document.write( "62.5, -25, 10, -4, 1.6, -.64, .256, -.1024, .04096, -.016384<BR>\n" );
document.write( "Then round these to three decimal places. </SPAN>\n" );
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