document.write( "Question 998305: Units sold (x) and profit(p) are linear. 150 units sold results in $200 profit and 200 units sold results in $3100 profit , write the profit function.\r
\n" ); document.write( "\n" ); document.write( "P =\r
\n" ); document.write( "\n" ); document.write( "Find the marginal profit?
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Algebra.Com's Answer #616106 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"P+=ax%2Bb\"\r
\n" ); document.write( "\n" ); document.write( "if \"150\" units sold results in $\"200\" profit, we have\r
\n" ); document.write( "\n" ); document.write( "\"200+=a%2A150%2Bb\"\r
\n" ); document.write( "\n" ); document.write( "\"200+=150a%2Bb\"...solve for \"b\"\r
\n" ); document.write( "\n" ); document.write( "\"b=200+-150a\"....eq.1\r
\n" ); document.write( "\n" ); document.write( "if \"200\" units sold results in $\"3100\" profit, we have \r
\n" ); document.write( "\n" ); document.write( "\"3100+=a%2A200%2Bb\"\r
\n" ); document.write( "\n" ); document.write( "\"3100+=200a%2Bb\"...solve for \"b\"\r
\n" ); document.write( "\n" ); document.write( "\"b=3100+-200a\"....eq.2\r
\n" ); document.write( "\n" ); document.write( "since left sides of eq.1 and eq.2 are same, equal right sides\r
\n" ); document.write( "\n" ); document.write( "\"200+-150a=3100+-200a\"...solve for \"a\"\r
\n" ); document.write( "\n" ); document.write( "\"200a+-150a=3100+-200\"\r
\n" ); document.write( "\n" ); document.write( "\"5cross%280%29a=290cross%280%29\"\r
\n" ); document.write( "\n" ); document.write( "\"5a=290\"\r
\n" ); document.write( "\n" ); document.write( "\"a=290%2F5\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28a=58%29\"\r
\n" ); document.write( "\n" ); document.write( "now find \"b\"\r
\n" ); document.write( "\n" ); document.write( "\"b=200+-150a\"....eq.1...substitute \"58\" for \"a\"\r
\n" ); document.write( "\n" ); document.write( "\"b=200+-150%2A58\"\r
\n" ); document.write( "\n" ); document.write( "\"b=200+-8700\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28b=-8500%29\"\r
\n" ); document.write( "\n" ); document.write( "so, your equation is:\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28P+=58x-8500%29\"\r
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