document.write( "Question 998213: Suppose that a cyclist began a 442 mile ride across the western edge of the state, at the same time that a car traveling toward it leaves the eastern edge of the state. If the bike and the car met after 8.5 hours and the car traveled 30.8 MPH faster than the bike, find the average rate of each \n" ); document.write( "
Algebra.Com's Answer #616069 by mananth(16946)\"\" \"About 
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Let cyclist speed be x mph
\n" ); document.write( "car speed = (x+38.5) mph\r
\n" ); document.write( "\n" ); document.write( "both of them take the same time to meet = 8.5 hours\r
\n" ); document.write( "\n" ); document.write( "Distance = 442 miles\r
\n" ); document.write( "\n" ); document.write( "Combined speed = 2x+38.5\r
\n" ); document.write( "\n" ); document.write( "t= d/r\r
\n" ); document.write( "\n" ); document.write( "8.5 = 442/(2x+38.5)\r
\n" ); document.write( "\n" ); document.write( "8.5(2x+38.5) =442\r
\n" ); document.write( "\n" ); document.write( "17x + 327.5 = 442\r
\n" ); document.write( "\n" ); document.write( "17x= 442-327.5\r
\n" ); document.write( "\n" ); document.write( "17x = 114.5\r
\n" ); document.write( "\n" ); document.write( "x=6.75 mph...cycle speed\r
\n" ); document.write( "\n" ); document.write( "add 38.5 to get car speed\r
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