document.write( "Question 998223: An airplane travels 1800 miles in 2.5 hours with the aid of a tail wind. It takes 3 hours for the return trip, flying against the same wind. Find the speed of the airplane in the still wind, and the speed of the wind. Airplane speed:___________miles per hour Wind speed:____________miles per hour, \n" ); document.write( "
Algebra.Com's Answer #616066 by mananth(16946)\"\" \"About 
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Plane speed =x mph
\n" ); document.write( "wind speed =y mph
\n" ); document.write( "against wind 3 hours
\n" ); document.write( "with wind 2.5 hours
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\n" ); document.write( "Distance against 1800 miles distance with 1800 miles
\n" ); document.write( "t=d/r against wind -
\n" ); document.write( "1800 / ( x - y )= 3
\n" ); document.write( "3 ( x - y ) = 1800
\n" ); document.write( "3 x - 3 y = 1800 ....................1
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\n" ); document.write( "1800 / ( x + y )= 2.50
\n" ); document.write( "2.50 ( x + y ) = 1800
\n" ); document.write( "2.50 x + 2.50 y = 1800 ...............2
\n" ); document.write( "Multiply (1) by 2 1/2
\n" ); document.write( "Multiply (2) by 3
\n" ); document.write( "we get
\n" ); document.write( "7.50 x + -8 y = 4500
\n" ); document.write( "7.50 x + 8 y = 5400
\n" ); document.write( "15 x = 9900
\n" ); document.write( "/ 15
\n" ); document.write( "x = 660 mph
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\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "3 x -3 y = 1800
\n" ); document.write( "1980 -3 y = 1800
\n" ); document.write( "-3 y = 1800 -1980
\n" ); document.write( "-3 y = -180 mph
\n" ); document.write( " y = 60
\n" ); document.write( "Plane speed 660 mph
\n" ); document.write( "wind speed 60 mph
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\n" ); document.write( "m.ananth@hotmail.ca
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