document.write( "Question 998028: An amount of money is invested at 3% and $2000 more is invested at 4%. If the interest earned is $920, how much was invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #616007 by fractalier(6550)\"\" \"About 
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Call the amount invested at 3%, x. The setup looks like this:
\n" ); document.write( ".03x + .04(2000+x) = 920
\n" ); document.write( ".03x + 80 + .04x = 920
\n" ); document.write( ".07x = 840
\n" ); document.write( "x = 12000 @ 3%
\n" ); document.write( "2000+x = 14000 @ 4%
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