document.write( "Question 998028: An amount of money is invested at 3% and $2000 more is invested at 4%. If the interest earned is $920, how much was invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #616007 by fractalier(6550)![]() ![]() You can put this solution on YOUR website! Call the amount invested at 3%, x. The setup looks like this: \n" ); document.write( ".03x + .04(2000+x) = 920 \n" ); document.write( ".03x + 80 + .04x = 920 \n" ); document.write( ".07x = 840 \n" ); document.write( "x = 12000 @ 3% \n" ); document.write( "2000+x = 14000 @ 4% \n" ); document.write( " |