document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=998030>Question 998030</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangular field is 92ft. The length is 4 ft. More than twice the width. Find the length and the width\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #616003 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=616003\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter = 2L + 2W = 92 ft<BR>\n" );
document.write( "L = 4 + 2W<BR>\n" );
document.write( "Substitute that into the first equation and get<BR>\n" );
document.write( "2(4 + 2W) + 2W = 92<BR>\n" );
document.write( "8 + 4W + 2W = 92<BR>\n" );
document.write( "6W + 8 = 92<BR>\n" );
document.write( "6W = 84<BR>\n" );
document.write( "W = 14 feet<BR>\n" );
document.write( "L = 32 feet </SPAN>\n" );
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