document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=998129>Question 998129</A>: <I><SPAN STYLE=\"word-break: break-all;\">  The width of a triangle is one-fifth as much as the length. The perimeter is 120cm. Find the length and the width.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #616002 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=616002\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter P = 2L + 2W = 120 cm<BR>\n" );
document.write( "W = (1/5)L or<BR>\n" );
document.write( "L = 5W<BR>\n" );
document.write( "Now substitute this in and get<BR>\n" );
document.write( "2(5W) + 2W = 120<BR>\n" );
document.write( "12W = 120<BR>\n" );
document.write( "W = 10 cm<BR>\n" );
document.write( "L = 50 cm </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );