document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=998051>Question 998051</A>: <I><SPAN STYLE=\"word-break: break-all;\"> sum of ages is 40 of two person after 10 year the age of person is twice the age of other person </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #615978 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=615978\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call their ages now x and y.<BR>\n" );
document.write( "Thus x + y = 40 or x = 40 - y<BR>\n" );
document.write( "x + 10 = 2(y + 10)<BR>\n" );
document.write( "Now substitute<BR>\n" );
document.write( "40 - y + 10 = 2y + 20<BR>\n" );
document.write( "50 - y = 2y + 20<BR>\n" );
document.write( "30 = 3y<BR>\n" );
document.write( "y = 10<BR>\n" );
document.write( "x = 30 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );