document.write( "Question 998070: I am trying to solve the problem: ln(x)-ln(2)=10
\n" ); document.write( "the way I thought this was supposed to be handled was:
\n" ); document.write( "1. ln(x)-ln(2)=10
\n" ); document.write( "2. ln(x-2)=10
\n" ); document.write( "3. ln(x-2)= e10
\n" ); document.write( "4. x-2=e10
\n" ); document.write( "5. x=e10+2\r
\n" ); document.write( "\n" ); document.write( "however when I receive the answer 22026.50, this is shown to be incorrect.
\n" ); document.write( "

Algebra.Com's Answer #615925 by fractalier(6550)\"\" \"About 
You can put this solution on YOUR website!
From
\n" ); document.write( "ln(x)-ln(2)=10
\n" ); document.write( "I would combine logs first...
\n" ); document.write( "ln(x/2) = 10
\n" ); document.write( "then exponentiate
\n" ); document.write( "(x/2) = e^10
\n" ); document.write( "then multiply by 2
\n" ); document.write( "x = 2e^10 = 44052.9
\n" ); document.write( "
\n" );