document.write( "Question 998070: I am trying to solve the problem: ln(x)-ln(2)=10
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document.write( "the way I thought this was supposed to be handled was:
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document.write( "1. ln(x)-ln(2)=10
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document.write( "2. ln(x-2)=10
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document.write( "3. ln(x-2)= e10
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document.write( "4. x-2=e10
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document.write( "5. x=e10+2\r
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document.write( "however when I receive the answer 22026.50, this is shown to be incorrect. \n" );
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Algebra.Com's Answer #615925 by fractalier(6550)![]() ![]() You can put this solution on YOUR website! From \n" ); document.write( "ln(x)-ln(2)=10 \n" ); document.write( "I would combine logs first... \n" ); document.write( "ln(x/2) = 10 \n" ); document.write( "then exponentiate \n" ); document.write( "(x/2) = e^10 \n" ); document.write( "then multiply by 2 \n" ); document.write( "x = 2e^10 = 44052.9 \n" ); document.write( " |