document.write( "Question 997949: Solve the systems of equations by substitution:
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document.write( "3x+y= -8
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document.write( "4x+3y=7
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document.write( "I have been working with different types of equations all night on homework and I'm not sure if I just don't understand it or if I'm doing something small wrong I just can't seem to get the correct answer. \n" );
document.write( "
Algebra.Com's Answer #615852 by addingup(3677)![]() ![]() You can put this solution on YOUR website! 3x+y= -8 \n" ); document.write( "4x+3y= 7 \n" ); document.write( "We can begin with either one of the equations, but since we have a \"y\" all by itself in the first equation, let's start with the first equation: \n" ); document.write( "3x+y= -8 \n" ); document.write( "y= -8-3x \n" ); document.write( "Now we plug this value for y into the second equation (Warning: If we substitute into the same equation we would get a true, but useless, statement. Always substitute into the other equation) \n" ); document.write( "4x+3(-8-3x)= 7 Now we can solve for x: \n" ); document.write( "4x+-24-9x= 7 \n" ); document.write( "= 4x-24-9x= 7 Add 24 on both sides and add x on left: \n" ); document.write( "-5x= 31 \n" ); document.write( "x= 31/-5= -6 1/5 And y?: \n" ); document.write( "y= -8-3(-6 1/5) \n" ); document.write( "y= -8+18 3/5 \n" ); document.write( "y= 26 3/5 \n" ); document.write( "J \n" ); document.write( " |