document.write( "Question 997949: Solve the systems of equations by substitution:
\n" ); document.write( "3x+y= -8
\n" ); document.write( "4x+3y=7
\n" ); document.write( "I have been working with different types of equations all night on homework and I'm not sure if I just don't understand it or if I'm doing something small wrong I just can't seem to get the correct answer.
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Algebra.Com's Answer #615852 by addingup(3677)\"\" \"About 
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3x+y= -8
\n" ); document.write( "4x+3y= 7
\n" ); document.write( "We can begin with either one of the equations, but since we have a \"y\" all by itself in the first equation, let's start with the first equation:
\n" ); document.write( "3x+y= -8
\n" ); document.write( "y= -8-3x
\n" ); document.write( "Now we plug this value for y into the second equation (Warning: If we substitute into the same equation we would get a true, but useless, statement. Always substitute into the other equation)
\n" ); document.write( "4x+3(-8-3x)= 7 Now we can solve for x:
\n" ); document.write( "4x+-24-9x= 7
\n" ); document.write( "= 4x-24-9x= 7 Add 24 on both sides and add x on left:
\n" ); document.write( "-5x= 31
\n" ); document.write( "x= 31/-5= -6 1/5 And y?:
\n" ); document.write( "y= -8-3(-6 1/5)
\n" ); document.write( "y= -8+18 3/5
\n" ); document.write( "y= 26 3/5
\n" ); document.write( "J
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