document.write( "Question 997898: A stereo cost $12 more than twice as much as a concert ticket. Together they cost $177. How much does each cost \n" ); document.write( "
Algebra.Com's Answer #615831 by addingup(3677)![]() ![]() You can put this solution on YOUR website! stereo= ticket times 2 plus 12. I'll call the ticket x \n" ); document.write( "stereo + tickets= 177 Now, in this formula, use the value above for stereo: \n" ); document.write( "ticket*2+12+ticket= 177 Before we continue with the answer, now that I explained the logic, let's set in a more elegant equation form. \n" ); document.write( "------------------ \n" ); document.write( "Let's call the ticket x: \n" ); document.write( "2x+12+x= 177 Add x on left and subtract 12 on both sides \n" ); document.write( "3x= 165 Divide both sides by 3 \n" ); document.write( "x= 55 is the price of the ticket. The stereo is: \n" ); document.write( "55*2+12= 122 \n" ); document.write( "--------------------- \n" ); document.write( "Proof: \n" ); document.write( "55+(55*2+12)= 177 \n" ); document.write( "55+(110+12)= 177 \n" ); document.write( "55+122= 177 \n" ); document.write( "177= 177 We have the correct answer \n" ); document.write( " |