document.write( "Question 85338: Of Calculus I:
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document.write( "Prove that the limit as x approaches zero from the right of the function
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document.write( "\"The square root of x times e to the power of the sine of pi over x\"
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document.write( "is equal to zero.
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document.write( "In mathematical terms, that is
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document.write( "Prove
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document.write( " lim
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document.write( "x->0+\r\n" );
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Algebra.Com's Answer #61582 by bucky(2189) ![]() You can put this solution on YOUR website! Find: \n" ); document.write( ". \n" ); document.write( "lim \n" ); document.write( "x->0+ \n" ); document.write( ". \n" ); document.write( "Since nobody else has taken a shot at this, maybe I can give you a way of looking at it. \n" ); document.write( ". \n" ); document.write( "Look at the exponent of e and recognize the limits on \n" ); document.write( "is limited to values between -1 and +1. So the exponent of e will range in value from \n" ); document.write( "-1 to +1. That means that the term: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "has a finite value ranging from \n" ); document.write( "is finite (and positive) the limiting factor in this problem is \n" ); document.write( "x is approaching 0+, the expression gets closer and closer to zero times the finite value \n" ); document.write( "of the term involving e. Therefore, the limit is zero, just as the problem proposes that \n" ); document.write( "you prove. \n" ); document.write( ". \n" ); document.write( "Hope this gets you on the right track and at least gives you a feel for a way of proving the \n" ); document.write( "premise. \n" ); document.write( " \n" ); document.write( " |