document.write( "Question 997872: When each of three numbers is added to twice the sum of the other two, the results are 64, 62 and 59. Determine the numbers (algebraically).\r
\n" ); document.write( "\n" ); document.write( "I have come up with the equations:
\n" ); document.write( "a+2(b+c)=64
\n" ); document.write( "b+2(a+c)=62
\n" ); document.write( "c+2(b+a)=59\r
\n" ); document.write( "\n" ); document.write( "I am unsure of how to further solve for the unknown values. \n" ); document.write( "
Algebra.Com's Answer #615819 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "    1    2    2      64\r\n" );
document.write( "    2    1    2      62\r\n" );
document.write( "    2    2    1      59\r\n" );
document.write( "\r\n" );
document.write( "-2R1 + R2 -> R2\r\n" );
document.write( "-2R1 + R3 -> R3\r\n" );
document.write( "\r\n" );
document.write( "    1    2    2      64\r\n" );
document.write( "    0   -3   -2     -66\r\n" );
document.write( "    0   -2   -3     -69\r\n" );
document.write( "\r\n" );
document.write( "-1/3R2 -> R2\r\n" );
document.write( "\r\n" );
document.write( "    1    2    2      64\r\n" );
document.write( "    0    1    2/3    22\r\n" );
document.write( "    0   -2   -3     -69\r\n" );
document.write( "\r\n" );
document.write( "2R2 + R3 -> R3\r\n" );
document.write( "\r\n" );
document.write( "    1    2    2      64\r\n" );
document.write( "    0    1    2/3    22\r\n" );
document.write( "    0    0   -5/3   -25  \r\n" );
document.write( "\r\n" );
document.write( "-3/5R3 -> R3\r\n" );
document.write( "\r\n" );
document.write( "    1    2    2      64\r\n" );
document.write( "    0    1    2/3    22\r\n" );
document.write( "    0    0    1      15\r\n" );
document.write( "\r\n" );
document.write( "-2/3R3 + R2 -> R2\r\n" );
document.write( "\r\n" );
document.write( "    1    2    2      64\r\n" );
document.write( "    0    1    0      12\r\n" );
document.write( "    0    0    1      15\r\n" );
document.write( "\r\n" );
document.write( "-2R2 - 2R3 + R1 -> R1\r\n" );
document.write( "\r\n" );
document.write( "    1    0    0      10\r\n" );
document.write( "    0    1    0      12\r\n" );
document.write( "    0    0    1      15\r\n" );
document.write( "
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it\r
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