document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=997877>Question 997877</A>: <I><SPAN STYLE=\"word-break: break-all;\"> there are four numbers such that each is the sum of the previous number and 4. Find the numbers if their sum is 64. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #615811 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=615811\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We'll call the first number x:<BR>\n" );
document.write( "x+x+4+x+4+4+x+4+4+4= 64<BR>\n" );
document.write( "Add all the x and all the 4 (or, for the 4, you can multiply 4*4):<BR>\n" );
document.write( "4x+24= 64 Subtract 24, both sides<BR>\n" );
document.write( "4x= 40 Divide both sides by 4<BR>\n" );
document.write( "x= 10<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "10+(10+4)+(10+4+4)+(10+4+4+4)= 64<BR>\n" );
document.write( "10+14+18+22= 64 These are your numbers. Add them up and see proof:<BR>\n" );
document.write( "64= 64 we have the correct answer </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );