document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=997843>Question 997843</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Mandy is twice as old as Jessica. Three years ago Mandy was three times as old as Jessica was then. Find the age of each girl now </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #615799 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=615799\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call their ages now m and j.  Thus<BR>\n" );
document.write( "m = 2j<BR>\n" );
document.write( "Three years ago,<BR>\n" );
document.write( "m-3 = 3(j-3)<BR>\n" );
document.write( "Now substitute for m and get<BR>\n" );
document.write( "2j-3 = 3(j-3)<BR>\n" );
document.write( "2j-3 = 3j-9<BR>\n" );
document.write( "Now subtract 2j and add nine to both sides and get<BR>\n" );
document.write( "6 = j<BR>\n" );
document.write( "m = 12 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );