document.write( "Question 997811: The sum of three numbers in a.p is 12 and the sum of their squares is 66. what are the numbers \n" ); document.write( "
Algebra.Com's Answer #615774 by ikleyn(52788)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "Let x be a middle number, then the first one is x-d and the third one is x+d, where d is the common difference.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The sum of three is 12. It means that \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x-d) + x + (x+d) = 12, or \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3x = 12, x = \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The sum of squares is 66. It means that\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Thus our progression is 1, 4, 7 or 7, 4, 1.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |