document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=997835>Question 997835</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of the digits of a two digit number is 7. When the digits are reversed the value of the number increased by 27. Find the number<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #615763 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=615763\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the tens digit x and the ones digit y.<BR>\n" );
document.write( "Thus x + y = 7<BR>\n" );
document.write( "Originally the value is 10x + y.<BR>\n" );
document.write( "Reversed its value is 10y + x.  This is 27 more than the original, so<BR>\n" );
document.write( "10y + x = 10x + y + 27<BR>\n" );
document.write( "or<BR>\n" );
document.write( "-9x + 9y = 27<BR>\n" );
document.write( "or<BR>\n" );
document.write( "-x + y = 3   now add the first equation and get<BR>\n" );
document.write( "x + y = 7<BR>\n" );
document.write( "2y = 10 <BR>\n" );
document.write( "y = 5<BR>\n" );
document.write( "x = 2<BR>\n" );
document.write( "The original number was 25.<BR>\n" );
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