document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=997833>Question 997833</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Eric walked 4 miles due south and then walked east. He is now 12 miles from his starting point. How far did he walk east? Round to the nearest tenth. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #615752 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=615752\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You have made a right triangle where the southern piece is one leg of length 4 miles, and the hypotenuse is 12 miles.  We need the eastern leg.  Call it b.  Use the Pythagoren Theorem:<BR>\n" );
document.write( "a^2 + b^2 = c^2<BR>\n" );
document.write( "4^2 + b^2 = 12^2<BR>\n" );
document.write( "16 + b^2 = 144   now subtract 16<BR>\n" );
document.write( "b^2 = 128<BR>\n" );
document.write( "b = sqrt(128) = 11.3 </SPAN>\n" );
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