document.write( "Question 997800: I have a problem that seems simple but I'm having an issue solving it. The problem is:
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\n" ); document.write( "Length of rectangle 5\" more then width. Area is 66\". What is length and width? L=w+5
\n" ); document.write( "66= w(w+5) I write this out as w^2+5w-66. Then I factor this so (w+11)(w-6) but I don't know how to finish. Can you help me?
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Algebra.Com's Answer #615742 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "Length of rectangle \"5\" more then width. Area is \"66\". What is length and width? \r
\n" ); document.write( "\n" ); document.write( "\"L=w%2B5\"\r
\n" ); document.write( "\n" ); document.write( "\"66=+w%28w%2B5%29\" \r
\n" ); document.write( "\n" ); document.write( "\"66=w%5E2%2B5w\"\r
\n" ); document.write( "\n" ); document.write( "\"0=w%5E2%2B5w-66\"\r
\n" ); document.write( "\n" ); document.write( " \"%28w%2B11%29%28w-6%29=0\"\r
\n" ); document.write( "\n" ); document.write( "solutions:\r
\n" ); document.write( "\n" ); document.write( "if \"%28w%2B11%29=0\"=>\"w=-11\"=> disregard negative solution because we are looking for the width and it cannot be negative number\r
\n" ); document.write( "\n" ); document.write( "if \"%28w-6%29=0\"=> \"highlight%28w=6%29\"\r
\n" ); document.write( "\n" ); document.write( "now find the length: \"L=w%2B5\"=>\"L=6%2B5\"=>\"highlight%28L=11%29\"\r
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