document.write( "Question 85363This question is from textbook ALGEBRA 1
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document.write( ": How do I solve 2/3x = the square root of 24x - 128? \n" );
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Algebra.Com's Answer #61570 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! How do I solve 2/3x = the square root of 24x - 128? \n" ); document.write( "This problem, as written, is ambiguous, a few brackets would do wonders: \n" ); document.write( "Do you mean: \n" ); document.write( " \n" ); document.write( "or \n" ); document.write( " \n" ); document.write( "or \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "The last has integer solutions, so will assume that is it: \n" ); document.write( ": \n" ); document.write( "Multiply equation by 3 and get rid of the denominator: \n" ); document.write( "2x = 3* \n" ); document.write( ": \n" ); document.write( "Square both sides and you have: \n" ); document.write( "4x^2 = 9(24x-128) \n" ); document.write( ": \n" ); document.write( "4x^2 = 216x - 1152 \n" ); document.write( ": \n" ); document.write( "4x^2 - 216x + 1152 = 0; arrange as a quadratic equation \n" ); document.write( ": \n" ); document.write( "Simplify, divide equation by 4 \n" ); document.write( "x^2 - 54x - 288 = 0 \n" ); document.write( ": \n" ); document.write( "Factors to: \n" ); document.write( "(x - 48)(x - 6) = 0 \n" ); document.write( ": \n" ); document.write( "Solutions are: x = +6 and x = +48 \n" ); document.write( ": \n" ); document.write( "You should check both solutions in the original equation \n" ); document.write( " |