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You can put this solution on YOUR website!
Do you have a specific equation you need to solve? IF so, you should post it. But I'll give you three examples you can use, find a few inequalities so you can practice, just follow my steps.
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\n" ); document.write( "Example 1:
\n" ); document.write( "4x+3 < -1 Subtract 3 from both sides:
\n" ); document.write( "4x < -4 Divide both sides by 4:
\n" ); document.write( "x < -1
\n" ); document.write( "You can write it in interval notation:
\n" ); document.write( "(-infinite, -1) from negative infinity to -1 but not including -1 If it was including -1 we would use a bracket ] and not a parenthesis )
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\n" ); document.write( "Example 2:
\n" ); document.write( "5x > 8x+27 Subtract 8x from both sides:
\n" ); document.write( "-3x > 27 Now divide both sides by -3 and remember that when you divide or multiply an inequality by a negative number you change the sign, like this:
\n" ); document.write( "-3x/-3 < 27/-3 Calculate and you get:
\n" ); document.write( "x < -9
\n" ); document.write( "In interval notation:
\n" ); document.write( "(-infinite, -9) Again, it's an inequality so we use a parenthesis to indicate that it goes up to -9 but without including -9.
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\n" ); document.write( "Example 3:
\n" ); document.write( "8x-5(4x+1) ≥ -1+2(4x-3)
\n" ); document.write( "8x-20x-5 ≥ -1+8x-6 Let's simplify by adding/subtracting on both sides:
\n" ); document.write( "-12x-5 ≥ -7+8x Now let's subtract 8x and add 5 to both sides:
\n" ); document.write( "-20x ≥ -2 Now let's divide both sides by -20, and remember, when we divide or multiply both sides of an inequality by a negative number we have to change the sign:
\n" ); document.write( "x= ≤ -2/-20 Now, on the right you have -/- and you know what happens when you either multiply or divide two negatives, right? - and - = +. So we simplify and rewrite:
\n" ); document.write( "x ≤ 1/10
\n" ); document.write( "In interval notation:
\n" ); document.write( "(-infinite, 1/10] (because it's an equal or smaller, the 1/10 is included)
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