document.write( "Question 997699: Tricky exponential decay word problem:\r
\n" ); document.write( "\n" ); document.write( "Suppose a small quantity of radon gas, which has a half-life of 3.8 days, is accidentally released into the air in a laboratory. If the resulting radiation level is 10% above the safe level, how long should the laboratory remain vacated? (Hint: To start with, determine what fraction of the \"resulting radiation level\" is the maximum safe level.) \r
\n" ); document.write( "\n" ); document.write( "The laboratory should remain vacated for ____days\r
\n" ); document.write( "\n" ); document.write( "Thank you
\n" ); document.write( "

Algebra.Com's Answer #615675 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
\"y=Ie%5E%28-kt%29\"
\n" ); document.write( "Find k using the given half-life.
\n" ); document.write( "\"ln%28y%29=ln%28I%29-kt\"
\n" ); document.write( "\"ln%28y%29-ln%28I%29=-kt\"
\n" ); document.write( "\"ln%28I%29-ln%28y%29=kt\"
\n" ); document.write( "\"kt=ln%28I%2Fy%29\"-----will be re-used later
\n" ); document.write( "\"k=%281%2Ft%29ln%28I%2Fy%29\"
\n" ); document.write( "substitute half life information data.
\n" ); document.write( "\"k=%281%2F3.8%29ln%281%2F%281%2F2%29%29\"
\n" ); document.write( "\"k=ln%282%29%2F3.8\"
\n" ); document.write( "\"k=0.1824\"
\n" ); document.write( "-
\n" ); document.write( "Refined Model, \"highlight%28y=Ie%5E%28-0.1824t%29%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The maximum safety level would be some 100%, not sure based on what units. Ten percent above the safety level would be some 110% of these units for radon gas. You want to calculate the time to decay from 110% to 100%.
\n" ); document.write( "-
\n" ); document.write( "\"system%28I=110%2C+y=100%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Look back at the derivation made earlier, and starting from the step,
\n" ); document.write( "\"kt=ln%28I%2Fy%29\"
\n" ); document.write( "\"highlight_green%28t=ln%28I%2Fy%29%2Fk%29\"
\n" ); document.write( "\"t=ln%28110%2F100%29%2F%280.1824%29\"
\n" ); document.write( "\"t=ln%2811%2F10%29%2F%280.1824%29\"
\n" ); document.write( "\"highlight%28t=0.5225%2Adays%29\"-----------near enough to say 13 hours.
\n" ); document.write( "
\n" );