document.write( "Question 997627: How do you find the vertex, value of p, axis of symmetry, focus, and directrix of each parabola with the equation X-1=-1/12y^2 \n" ); document.write( "
Algebra.Com's Answer #615646 by josgarithmetic(39617)\"\" \"About 
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The equation written correctly, or in more precise manner is \"x-1=-%281%2F12%29y%5E2\".
\n" ); document.write( "This is a parabola with symmetry axis parallel to the x-axis, and graph of parabola opens to the left, as indicated by coefficient NEGATIVE 1/12. This coefficient \"-1%2F12\" tells you information about how far is focus and directrix from the vertex. YOUR equation's vertex is (1,0).\r
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\n" ); document.write( "\n" ); document.write( "Learn better how this works through these two videos:\r
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\n" ); document.write( "\n" ); document.write( "Derive equation for parabola from focus and directrix\r
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\n" ); document.write( "\n" ); document.write( "Equation for parabola from directrix and focus but vertex is NOT at the Origin\r
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\n" ); document.write( "\n" ); document.write( "According to the form of the equation used in the derivations, \"4p=%281%2F12%29\", and |p| is how far vertex is from either focus or directrix.
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\n" ); document.write( "\"p=%281%2F4%29%281%2F12%29\"
\n" ); document.write( "\"p=1%2F48\"\r
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\n" ); document.write( "\n" ); document.write( "Focus is on the concave side, to left of the vertex.
\n" ); document.write( "\"x=1-1%2F48\"
\n" ); document.write( "\"x=48%2F48-1%2F48\"
\n" ); document.write( "\"x=47%2F48\" and \"y=0\", this y-value unchanged.
\n" ); document.write( "FOCUS: ( 47/48, 0 )\r
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\n" ); document.write( "\n" ); document.write( "Directrix would be on the other side and is the vertical line \"x=1%261%2F48\".
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