document.write( "Question 997637: Given the equation \"4x%5E2%2B8x%2Bk=0\" , for what values of k will the equation have a repeated root, 2 real roots, and 3 values of k that will give the equation rational roots. I understand what it means to have those types of roots, I just don't understand how you would get to those specific answers. Like, I know how to find and imaginary root for this equation: \"+%5B-infinite%3Ck%3Cless+than+0%5D+\" . Would that be right? \n" ); document.write( "
Algebra.Com's Answer #615643 by Boreal(15235)\"\" \"About 
You can put this solution on YOUR website!
4x^2+8x+k=0
\n" ); document.write( "4x^2+8x=-k
\n" ); document.write( "Factor out 4.
\n" ); document.write( "4(x^2+2x)= -k but k can be any constant, so it doesn't have to be divided by 4.
\n" ); document.write( "If you complete the square, the roots will be the same, -1.
\n" ); document.write( "4(x^2+2x+1)= -(k)+4, adding 4 to both sides
\n" ); document.write( "4(x+1)^2= -k +4
\n" ); document.write( "The right side has to equal zero for completing the square to give two roots of -1
\n" ); document.write( "-k=-4
\n" ); document.write( "k=4
\n" ); document.write( "4x^2+8x+4=0
\n" ); document.write( "\"graph%28300%2C200%2C-10%2C10%2C-10%2C10%2C4x%5E2%2B8x%2B4%29\"
\n" ); document.write( "========
\n" ); document.write( "Two real roots can be many things, so long as the discriminant b^2-4ac is positive.
\n" ); document.write( "b^2>4ak, since k is acting as c
\n" ); document.write( "64>16k
\n" ); document.write( "k<4 will work
\n" ); document.write( "\"graph%28300%2C200%2C-10%2C10%2C-10%2C10%2C4x%5E2%2B8x%2B2%2C4x%5E2%2B8x-2%29\"
\n" ); document.write( "=========
\n" ); document.write( "Rational roots work if the discriminant gives a perfect square, for all parts of the quadratic formula will be a fraction with nothing but integers.
\n" ); document.write( "b^2-16k has to be a perfect square
\n" ); document.write( "64-16k\r
\n" ); document.write( "\n" ); document.write( "k=0 works and roots are 4 and 0
\n" ); document.write( "k=3 :(1/8){-8 +/- sqrt(16){=(1/8)(-4) and (1/8)(-12)
\n" ); document.write( "k= -36/16 (1/8) (-8 +/- sqrt (100) and (1/8)(-8+10), (1/8) (-8-10) or (10/8), (-18/8)
\n" ); document.write( "
\n" ); document.write( "
\n" );