document.write( "Question 997637: Given the equation , for what values of k will the equation have a repeated root, 2 real roots, and 3 values of k that will give the equation rational roots. I understand what it means to have those types of roots, I just don't understand how you would get to those specific answers. Like, I know how to find and imaginary root for this equation:
. Would that be right? \n" );
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Algebra.Com's Answer #615643 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! 4x^2+8x+k=0 \n" ); document.write( "4x^2+8x=-k \n" ); document.write( "Factor out 4. \n" ); document.write( "4(x^2+2x)= -k but k can be any constant, so it doesn't have to be divided by 4. \n" ); document.write( "If you complete the square, the roots will be the same, -1. \n" ); document.write( "4(x^2+2x+1)= -(k)+4, adding 4 to both sides \n" ); document.write( "4(x+1)^2= -k +4 \n" ); document.write( "The right side has to equal zero for completing the square to give two roots of -1 \n" ); document.write( "-k=-4 \n" ); document.write( "k=4 \n" ); document.write( "4x^2+8x+4=0 \n" ); document.write( " \n" ); document.write( "======== \n" ); document.write( "Two real roots can be many things, so long as the discriminant b^2-4ac is positive. \n" ); document.write( "b^2>4ak, since k is acting as c \n" ); document.write( "64>16k \n" ); document.write( "k<4 will work \n" ); document.write( " \n" ); document.write( "========= \n" ); document.write( "Rational roots work if the discriminant gives a perfect square, for all parts of the quadratic formula will be a fraction with nothing but integers. \n" ); document.write( "b^2-16k has to be a perfect square \n" ); document.write( "64-16k\r \n" ); document.write( "\n" ); document.write( "k=0 works and roots are 4 and 0 \n" ); document.write( "k=3 :(1/8){-8 +/- sqrt(16){=(1/8)(-4) and (1/8)(-12) \n" ); document.write( "k= -36/16 (1/8) (-8 +/- sqrt (100) and (1/8)(-8+10), (1/8) (-8-10) or (10/8), (-18/8) \n" ); document.write( " \n" ); document.write( " |