document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=997639>Question 997639</A>: <I><SPAN STYLE=\"word-break: break-all;\"> You have 70000 dollars to invest for 7 years. Which investment will provide the gather return, 5 percent compounded yearly or 4.75 compounded monthly?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #615640 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=615640\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> It is the difference between<BR>\n" );
document.write( "{1+.05)^7=1.407 (that is how much the initial principal is multiplied by.<BR>\n" );
document.write( "(1+(.0475/12))^84=1.394<BR>\n" );
document.write( "The first one is better.<BR>\n" );
document.write( "P=Po{1+rate/compoundings per year)^number of years*compounding per year </SPAN>\n" );
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