document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=997602>Question 997602</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The lengths of the sides of a triangle are consecutive odd integers.<BR>\n" );
document.write( " if the perimeter is one less than four times the shortest side. find the length of each side\r<BR>\n" );
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document.write( "***please write the equation used to solve this** </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #615631 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=615631\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Consecutive odd integers. How many numbers from 1 to3? From 3 to 5? From 5 to 7? The answer is two, there are two numbers between odds just like there are two numbers between evens: one, two AND three; three four ANd five.<BR>\n" );
document.write( "So we have that:<BR>\n" );
document.write( "a+a+2+a+2+2= 4a-1<BR>\n" );
document.write( "3a+6= 4a-1 Add 1 to both sides:<BR>\n" );
document.write( "3a+7= 4a Subtract 3a from both sides<BR>\n" );
document.write( "7= 4a<BR>\n" );
document.write( "or<BR>\n" );
document.write( "4a= 7 Now divide both sides by 4<BR>\n" );
document.write( "a= 7/4 The denominator is bigger than the numerator, it means we have a mixed number:<BR>\n" );
document.write( "4 goes into 7 one time and we have a remainder of 3:<BR>\n" );
document.write( "1 3/4 Since we are talking length, let's convert to decimal: 3/4= 0.75:<BR>\n" );
document.write( "1.75 is the length of the shortest side, let's call it side a<BR>\n" );
document.write( "side b: 1.75+2= 3.75<BR>\n" );
document.write( "side c: 1.75+2+2= 5.75 </SPAN>\n" );
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