document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=997497>Question 997497</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The ratio of mass of gold and copper in a jewellery piece is 5:8. if the mass of alloy is 18.2 kg , find the mass of gold in it.?   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #615630 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=615630\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the mass of gold x.<BR>\n" );
document.write( "Since there is more copper, at a ratio of 8 to 5, the amount of copper is (8/5)x.<BR>\n" );
document.write( "Added together, they have a mass of 18.2 kg.  Thus<BR>\n" );
document.write( "x + (8/5)x = 18.2<BR>\n" );
document.write( "(13/5)x = 18.2   ==> 13/5 = 2.6<BR>\n" );
document.write( "x = 18.2 / 2.6<BR>\n" );
document.write( "x = 7 kg gold </SPAN>\n" );
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