document.write( "Question 997465: 1/4 journey at 25 km/h 1/3 at 30km/h and rest at 50km/h.find average speed \n" ); document.write( "
Algebra.Com's Answer #615617 by ankor@dixie-net.com(22740)\"\" \"About 
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1/4 journey at 25 km/h 1/3 at 30km/h and rest at 50km/h.
\n" ); document.write( "find average speed
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\n" ); document.write( "Let a = the average speed
\n" ); document.write( "We can make this easy, choose a convenient value for the distance of the trip
\n" ); document.write( "Dist = 120 km
\n" ); document.write( "them
\n" ); document.write( "\"1%2F4\"*120 = 30 km
\n" ); document.write( "\"1%2F3\"*120 = 40 km
\n" ); document.write( "and
\n" ); document.write( "50 km = the remainder of the trip
\n" ); document.write( ":
\n" ); document.write( "Write a time equation; time = dist/speed
\n" ); document.write( "\"30%2F25\" + \"40%2F30\" + \"50%2F50\" = \"120%2Fa\"
\n" ); document.write( "Multiply equation by 150a, cancel the denominators and you have
\n" ); document.write( "6a(30) + 5a(40) + 3a(50) = 150(120)
\n" ); document.write( "180a + 200a + 150a = 18000
\n" ); document.write( "530a = 18000
\n" ); document.write( "a = 18000/530
\n" ); document.write( "a = 33.96 ~ 34 km/hr is the average speed
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