document.write( "Question 997465: 1/4 journey at 25 km/h 1/3 at 30km/h and rest at 50km/h.find average speed \n" ); document.write( "
Algebra.Com's Answer #615617 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! 1/4 journey at 25 km/h 1/3 at 30km/h and rest at 50km/h. \n" ); document.write( "find average speed \n" ); document.write( ": \n" ); document.write( "Let a = the average speed \n" ); document.write( "We can make this easy, choose a convenient value for the distance of the trip \n" ); document.write( "Dist = 120 km \n" ); document.write( "them \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "and \n" ); document.write( "50 km = the remainder of the trip \n" ); document.write( ": \n" ); document.write( "Write a time equation; time = dist/speed \n" ); document.write( " \n" ); document.write( "Multiply equation by 150a, cancel the denominators and you have \n" ); document.write( "6a(30) + 5a(40) + 3a(50) = 150(120) \n" ); document.write( "180a + 200a + 150a = 18000 \n" ); document.write( "530a = 18000 \n" ); document.write( "a = 18000/530 \n" ); document.write( "a = 33.96 ~ 34 km/hr is the average speed \n" ); document.write( " |