document.write( "Question 997569: An investment of $10,000 with Barnes Bank earns a 2.42% APR compounded monthly. \r
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document.write( "Determine how long it will take the investment to double\r
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document.write( "Thank you in advance.
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Algebra.Com's Answer #615599 by addingup(3677)![]() ![]() You can put this solution on YOUR website! A= P(1+r/m)^mt, where \n" ); document.write( "A is the future money, in your case 2 x 10,000= 20,000 \n" ); document.write( "P is the Principal, the amount we've invested = 10,000 \n" ); document.write( "r is the rate, the interest rate = 2.42% \n" ); document.write( "n is the number of compounding periods in one year = 12 \n" ); document.write( "t is the number of years, this is what we'll find out. \n" ); document.write( "------------------------------- \n" ); document.write( "You double your money when A/P= 2, regardless of the amount of money. It's the interest rate and the time that dictate it. So here we go (NOTE: My calculator and I are not infallible. Do the math wherever you see calculations): \n" ); document.write( "(1+r/m)^mt = 2 \n" ); document.write( "(1+.0242/12)^12t = 2 \n" ); document.write( "(1.00202)^12t = 2 \n" ); document.write( "Take the log of both sides \n" ); document.write( "ln(1.00202)^12t = ln(2) \n" ); document.write( "12t[ln(1.00202) = ln(2) \n" ); document.write( "t= ln(2)/12*ln(1.00202) \n" ); document.write( "t= 28.6 years \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |