document.write( "Question 997544: Boy and Girl sells mixtures of almonds and raisins. A kilogram of almonds and raisins cost $300 and $125, respectively. If the final cost of the mixture is $1,400 and the mixture contaion 7.5kg of the raisins, how many kilograms of almonds were mixed? \n" ); document.write( "
Algebra.Com's Answer #615583 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
Learn from this lesson:
\n" ); document.write( "http://www.algebra.com/my/Two-Part-Mixture-with-one-material-quantity-unknown.lesson?content_action=show_dev\r
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\n" ); document.write( "\n" ); document.write( "The cost per kilogram can be found or thought as \"%28moneyCost%29%2F%28massKilograms%29\".
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\n" ); document.write( "On the other hand, you could just account for the cost of the mixture.
\n" ); document.write( "Think, \"massRaisins%2ApriceRaisins%2BmassAlmonds%2ApriceAlmonds=costMixture\".\r
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\n" ); document.write( "\n" ); document.write( "y, the amount of the almonds (because you are given how much raisins).\r
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\n" ); document.write( "\n" ); document.write( "\"%287.5%2A125%2B300%2Ay%29=1400\"\r
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\n" ); document.write( "\n" ); document.write( "Yes, you can manage the solution focused on price, but looking at accounting for cost seems
\n" ); document.write( "more straightforward here. The price can be found, since you know mass of y+7.5 mixture
\n" ); document.write( "will cost $1400; but the question asks for a material quantity and expects a given mixture COST.\r
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\n" ); document.write( "\n" ); document.write( "Solve \"highlight_green%287.5%2A125%2B300%2Ay=1400%29\" for y.
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\n" ); document.write( "\"300y=1400-7.5%2A125\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=%281400-7.5%2A125%29%2F300\"-----compute this.
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