document.write( "Question 85400: 21. Given: Ray ST bisects Angle(<) RSV
\n" ); document.write( " m< RST= x+y
\n" ); document.write( " m< TSV= 2x-2y
\n" ); document.write( " m< RSV= 64 degrees
\n" ); document.write( " Find: x and y
\n" ); document.write( "It also gives a diagram before it which i will try and describe:
\n" ); document.write( "It is a pic of an angle split in two. the vertex is named s and the top ray has the endpoint called r and the middle endpoint it t and the bottom endpoint is v. I have tried to explain the diagram but i don't think i did it very well. oh, well.
\n" ); document.write( "if you go to this picture site and it has the picture but just different names for the points: http://education.yahoo.com/homework_help/math_help/solutionimages/minigeogt/1/1/1/minigeogt_1_1_1_13_1/f-37-49-oyo-1.gif
\n" ); document.write( "I'm sorry if you are asking what in the world is she talking about because it is understandable!
\n" ); document.write( "thank you if you find the answer!
\n" ); document.write( "-Athena
\n" ); document.write( "

Algebra.Com's Answer #61557 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Since m< RST and m< TSV are half of m< RSV, we know this expression is true:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"m%3CRST=%281%2F2%29%2A64=32\"
\n" ); document.write( "\"m%3CTSV=%281%2F2%29%2A64=32\"\r
\n" ); document.write( "\n" ); document.write( "Also, since m< RST= x+y and m< TSV= 2x-2y, we can set up the following system of equations:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%2By=32\"
\n" ); document.write( "\"2x-2y=32\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now we can solve for x and y by addition/elimination:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: Solving a System of Linear Equations by Elimination/Addition

\n" ); document.write( "
\n" ); document.write( " Lets start with the given system of linear equations
\n" ); document.write( "
\n" ); document.write( " \"1%2Ax%2B1%2Ay=32\"
\n" ); document.write( " \"2%2Ax-2%2Ay=32\"
\n" ); document.write( "
\n" ); document.write( " In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for y, we would have to eliminate x (or vice versa).
\n" ); document.write( "
\n" ); document.write( " So lets eliminate x. In order to do that, we need to have both x coefficients that are equal but have opposite signs (for instance 2 and -2 are equal but have opposite signs). This way they will add to zero.
\n" ); document.write( "
\n" ); document.write( " So to make the x coefficients equal but opposite, we need to multiply both x coefficients by some number to get them to an equal number. So if we wanted to get 1 and 2 to some equal number, we could try to get them to the LCM.
\n" ); document.write( "
\n" ); document.write( " Since the LCM of 1 and 2 is 2, we need to multiply both sides of the top equation by 2 and multiply both sides of the bottom equation by -1 like this:
\n" ); document.write( "
\n" ); document.write( " \"2%2A%281%2Ax%2B1%2Ay%29=%2832%29%2A2\" Multiply the top equation (both sides) by 2
\n" ); document.write( " \"-1%2A%282%2Ax-2%2Ay%29=%2832%29%2A-1\" Multiply the bottom equation (both sides) by -1
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So after multiplying we get this:
\n" ); document.write( " \"2%2Ax%2B2%2Ay=64\"
\n" ); document.write( " \"-2%2Ax%2B2%2Ay=-32\"
\n" ); document.write( "
\n" ); document.write( " Notice how 2 and -2 add to zero (ie \"2%2B-2=0\")
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Now add the equations together. In order to add 2 equations, group like terms and combine them
\n" ); document.write( " \"%282%2Ax-2%2Ax%29%2B%282%2Ay%2B2%2Ay%29=64-32\"
\n" ); document.write( "
\n" ); document.write( " \"%282-2%29%2Ax%2B%282%2B2%29y=64-32\"
\n" ); document.write( "
\n" ); document.write( " \"cross%282%2B-2%29%2Ax%2B%282%2B2%29%2Ay=64-32\" Notice the x coefficients add to zero and cancel out. This means we've eliminated x altogether.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So after adding and canceling out the x terms we're left with:
\n" ); document.write( "
\n" ); document.write( " \"4%2Ay=32\"
\n" ); document.write( "
\n" ); document.write( " \"y=32%2F4\" Divide both sides by \"4\" to solve for y
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"y=8\" Reduce
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Now plug this answer into the top equation \"1%2Ax%2B1%2Ay=32\" to solve for x
\n" ); document.write( "
\n" ); document.write( " \"1%2Ax%2B1%288%29=32\" Plug in \"y=8\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"1%2Ax%2B8=32\" Multiply
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"1%2Ax=32-8\" Subtract \"8\" from both sides
\n" ); document.write( "
\n" ); document.write( " \"1%2Ax=24\" Combine the terms on the right side
\n" ); document.write( "
\n" ); document.write( " \"cross%28%281%2F1%29%281%29%29%2Ax=%2824%29%281%2F1%29\" Multiply both sides by \"1%2F1\". This will cancel out \"1\" on the left side.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"x=24\" Multiply the terms on the right side
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So our answer is
\n" ); document.write( "
\n" ); document.write( " \"x=24\", \"y=8\"
\n" ); document.write( "
\n" ); document.write( " which also looks like
\n" ); document.write( "
\n" ); document.write( " (\"24\", \"8\")
\n" ); document.write( "
\n" ); document.write( " Notice if we graph the equations (if you need help with graphing, check out this solver)
\n" ); document.write( "
\n" ); document.write( " \"1%2Ax%2B1%2Ay=32\"
\n" ); document.write( " \"2%2Ax-2%2Ay=32\"
\n" ); document.write( "
\n" ); document.write( " we get
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " graph of \"1%2Ax%2B1%2Ay=32\" (red) \"2%2Ax-2%2Ay=32\" (green) (hint: you may have to solve for y to graph these) and the intersection of the lines (blue circle).
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " and we can see that the two equations intersect at (\"24\",\"8\"). This verifies our answer.
\n" ); document.write( "
\n" ); document.write( "
\n" );