document.write( "Question 997502: 4a-3(a-(2a+1)) \n" ); document.write( "
Algebra.Com's Answer #615545 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
you want to simplify 4a-3(a-(2a+1))\r
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\n" ); document.write( "\n" ); document.write( "start with 4a-3(a-(2a+1))\r
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\n" ); document.write( "\n" ); document.write( "resolve the inner parentheses to get:\r
\n" ); document.write( "\n" ); document.write( "4a-3(a-(2a+1)) becomes:
\n" ); document.write( "4a - 3(a - 2a - 1) which becomes:
\n" ); document.write( "4a - 3(-a - 1)\r
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\n" ); document.write( "\n" ); document.write( "resolve the parentheses to get:\r
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\n" ); document.write( "\n" ); document.write( "4a + 3a + 3\r
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\n" ); document.write( "\n" ); document.write( "combine like terms to get:\r
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\n" ); document.write( "\n" ); document.write( "7a + 3\r
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\n" ); document.write( "\n" ); document.write( "the final expression is equivalent to the original expression.\r
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\n" ); document.write( "\n" ); document.write( "a quick way to see if you got it right is to give a random value to a and then evaluate the original expression and the final expression.\r
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\n" ); document.write( "\n" ); document.write( "if they both give you the same answer, then you got it right.\r
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\n" ); document.write( "\n" ); document.write( "i used a = 5 and got 38 from both expressions so i'm reasonably confident that i got it right.\r
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