document.write( "Question 997462: Eighty ounces of a 50% gold alloy are mixed with 20 oz of a 10% gold alloy. Find the percent concentration of the resulting gold alloy. \n" ); document.write( "
Algebra.Com's Answer #615533 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Eighty ounces of a 50% gold alloy are mixed with 20 oz of a 10% gold alloy. Find the percent concentration of the resulting gold alloy. \n" ); document.write( " percent concentration of the resulting gold \n" ); document.write( "50%*80+10%*20=(40+2)/100=42% \n" ); document.write( " percent concentration of the resulting gold =42% \n" ); document.write( " \n" ); document.write( " |