document.write( "Question 997462: Eighty ounces of a 50% gold alloy are mixed with 20 oz of a 10% gold alloy. Find the percent concentration of the resulting gold alloy. \n" ); document.write( "
Algebra.Com's Answer #615533 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
Eighty ounces of a 50% gold alloy are mixed with 20 oz of a 10% gold alloy. Find the percent concentration of the resulting gold alloy.
\n" ); document.write( " percent concentration of the resulting gold
\n" ); document.write( "50%*80+10%*20=(40+2)/100=42%
\n" ); document.write( " percent concentration of the resulting gold =42%
\n" ); document.write( "
\n" ); document.write( "
\n" );