document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=997434>Question 997434</A>: <I><SPAN STYLE=\"word-break: break-all;\"> kevin and randy muise have a jar containing 82 coins, all of which ae either quarters or nickles. The total value of the coins In the jar is 13.30. How many of each type of coin do they have?<BR>\n" );
document.write( " The jar contains how many quarters<BR>\n" );
document.write( "How many nickles? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #615518 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=615518\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> q+n= 82. Subtract n on both sides of the equal sign and we have:<BR>\n" );
document.write( "q= 82-n<BR>\n" );
document.write( "0.25q+0.10n= 13.30 Now, in this formula, substitute the value of q:<BR>\n" );
document.write( "0.25(82-n)+0.10n= 13.30<BR>\n" );
document.write( "20.50-0.25n+0.10n= 13.30 Add n on left and subtract 20.50 on both sides<BR>\n" );
document.write( "-0.15n= -7.20 Now divide both sides by -0.15<BR>\n" );
document.write( "n= -7.20/-0.15 OK, remember that -/- = +:<BR>\n" );
document.write( "n= 48 They have 48 nickels and: <BR>\n" );
document.write( "82-48= 34quarters.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "48*0.10= 4.80<BR>\n" );
document.write( "34*0.25= 8.50<BR>\n" );
document.write( "-----------------<BR>\n" );
document.write( "Total.....13.30 We have the correct answer </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );