document.write( "Question 997308: how do I solve a number is decreased by 30% and then doubled to be 91. What was the original number? \n" ); document.write( "
Algebra.Com's Answer #615458 by KMST(5328)\"\" \"About 
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\"x\"= the original number
\n" ); document.write( "When it is decreased by \"%2230%25%22\", what is left is
\n" ); document.write( "\"%22100%25%22-%2230%25%22=%2270%25%22=70%2F100=0.7\" of \"x\" .
\n" ); document.write( "That is \"0.7x\" .
\n" ); document.write( "When \"0.7x\" is doubled, the result is
\n" ); document.write( "\"2%2A%280.7x%29\" , and that equals \"91\" .
\n" ); document.write( "The equation that state that is
\n" ); document.write( "\"2%2A%280.7x%29=91\" .
\n" ); document.write( "Solving:
\n" ); document.write( "\"2%2A%280.7x%29=91\" can be simplified to \"1.4x=91\" , because
\n" ); document.write( "\"2%2A%280.7x%29=91\"<-->\"%282%2A0.7%29x=91\"<-->\"1.4x=91\" .
\n" ); document.write( "then,
\n" ); document.write( "\"1.4x=91\"-->\"x=91%2F1.4\"-->\"x=65\"
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